A light source, which emits two wavelengths λ 1 = 400 nm and λ 2 = 600 nm, is used in a Young's double slit experiment. If recorded fringe widths for λ 1 and λ 2 are β 1 and β 2 and the number of fringes for them within a distance y on one side of the central maximum are m 1 and m 2 , respectively, then the incorrect statment is
Text Solution
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β = 
∴ λ 2 > λ 1 so β 2 > β 1
No of fringes in a given width (m) = 
⇒ m 2 < m 1
3 rd maximum of λ 2 = 
5 th minimum of λ 1 = 
So, 3 rd maxima of λ 2 will meet with 5 th minimum of λ 1
Angular sepration = 
⇒ Angular seperation for λ 1 will be lesser
β = ∴ λ 2 > λ 1 vr% β 2 > β 1
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